18=-7x+x^2

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Solution for 18=-7x+x^2 equation:



18=-7x+x^2
We move all terms to the left:
18-(-7x+x^2)=0
We get rid of parentheses
-x^2+7x+18=0
We add all the numbers together, and all the variables
-1x^2+7x+18=0
a = -1; b = 7; c = +18;
Δ = b2-4ac
Δ = 72-4·(-1)·18
Δ = 121
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{121}=11$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(7)-11}{2*-1}=\frac{-18}{-2} =+9 $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(7)+11}{2*-1}=\frac{4}{-2} =-2 $

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